Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set: 23


$i\sqrt 3$

Work Step by Step

$\frac{\sqrt (-9)}{\sqrt 3}=\sqrt (\frac{-9}{3})=\sqrt (-3)=\sqrt (-1\times3)=\sqrt -1\times\sqrt 3=i\sqrt 3$ We know that $\sqrt -1=i$, because $i^{2}=-1$.
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