Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set - Page 463: 77

Answer

$7$

Work Step by Step

Using $(a+b)(a-b)=a^2-b^2$ or the product of the sum and difference of like terms, the expression $ (\sqrt{6}+i)(\sqrt{6}-i) $ simplifies to \begin{array}{l} (\sqrt{6})^2-(i)^2 \\= 6-i^2 \\= 6-(-1) \\= 7 .\end{array}
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