Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set: 20

Answer

$-2\sqrt 3$

Work Step by Step

$\sqrt -2 \times \sqrt -6=\sqrt (4\times-1\times-1\times3)=\sqrt 4\times\sqrt -1\times\sqrt -1\times\sqrt 3=2\times i\times i\times\sqrt 3=2\times i^{2}\times\sqrt 3=-2\sqrt 3$ We know that $\sqrt -1=i$ and that $i^{2}=-1$.
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