Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set: 10

Answer

$4i\sqrt 2$

Work Step by Step

$\sqrt(-32)=\sqrt (16\times-1\times2)=\sqrt 16\times\sqrt -1\times\sqrt 2=4i\sqrt 2$ We know that $\sqrt -1=i$, because $i^{2}=-1$.
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