Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set - Page 463: 5

Answer

-4

Work Step by Step

$-\sqrt16=-(\sqrt 16)=-(4)=-4$ We know that $\sqrt 16=4$, because $4^{2}=16$. In this case, we are finding the opposite of $\sqrt 16$.
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