Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set: 35

Answer

$18+12i$

Work Step by Step

We can use the distributive property to simplify the given expression. $6i(2-3i)=(6i)(2)+(6i)(-3i)=12i-18i^{2}=$ $12i-(18\times-1)=12i-(-18)=12i+18=18+12i$ We know that $i^{2}=-1$.
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