## Intermediate Algebra (6th Edition)

$18+12i$
We can use the distributive property to simplify the given expression. $6i(2-3i)=(6i)(2)+(6i)(-3i)=12i-18i^{2}=$ $12i-(18\times-1)=12i-(-18)=12i+18=18+12i$ We know that $i^{2}=-1$.