Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set: 24

Answer

$i\sqrt 4.9$

Work Step by Step

$\frac{\sqrt (49)}{\sqrt (-10)}=\sqrt (-\frac{49}{10})=\sqrt (-4.9)=\sqrt (-1\times4.9)=\sqrt -1\times\sqrt 4.9=i\sqrt 4.9$ We know that $\sqrt -1=i$, because $i^{2}=-1$.
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