Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set - Page 463: 34

Answer

$-22+0i$

Work Step by Step

$-2i\times-11i=(-2\times-11)\times(i\times i)=22\times i^{2}=22\times-1=-22=-22+0i$ We know that $i^{2}=-1$.
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