Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set: 18

Answer

$-\sqrt 33$

Work Step by Step

$\sqrt -11 \times \sqrt -3=\sqrt (-1\times-1\times11\times3)=\sqrt -1\times\sqrt -1\times\sqrt 33=i\times i\times\sqrt 33=i^{2}\sqrt 33=-\sqrt 33$ We know that $\sqrt -1=i$ and that $i^{2}=-1$.
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