Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set - Page 463: 70

Answer

$\dfrac{15+10i}{13}$

Work Step by Step

Multiplying by the conjugate of the denominator, the expression $ \dfrac{5}{3-2i} $ simplifies to \begin{array}{l} \dfrac{5}{3-2i} \cdot \dfrac{3+2i}{3+2i} \\\\= \dfrac{15+10i}{9-4i^2} \\\\= \dfrac{15+10i}{9-4(-1)} \\\\= \dfrac{15+10i}{13} .\end{array}
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