Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set - Page 463: 59

Answer

$20$

Work Step by Step

Using $i^2=-1$, the expression $ (6-2i)(3+i) $ simplifies to \begin{array}{l} 6(3)+6(i)-2i(3)-2i(i) \text{(use the FOIL method)} \\= 18+6i-6i-2i^2 \\= 18-2(-1) \\= 20 .\end{array}
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