Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises: 86

Answer

$-32x^{25}$

Work Step by Step

According to the power rule for exponents, $(a^{m})^{n}=a^{mn}$ (where $m$ and $n$ are integers and $a$ is a real number). Therefore, $(-2x^{5})^{5}=(-1\times2\times x^{5})^{5}=(-1)^{1\times5}\times2^{1\times5}\times x^{5\times5}=(-1)^{5}\times2^{5}\times x^{25}=-1\times32\times x^{25}=-32x^{25}$.
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