Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises: 52

Answer

$-\frac{1}{32x^{5}}$

Work Step by Step

According to the negative exponent rule, $a^{-n}=\frac{1}{a^{n}}$. Therefore, $(-2x)^{-5}=\frac{1}{(-2x)^{5}}=\frac{1}{(-2)^{5}x^{5}}=\frac{1}{-32x^{5}}=-\frac{1}{32x^{5}}$.
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