Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises: 53

Answer

$\frac{11}{30}$

Work Step by Step

According to the negative exponent rule, $a^{-n}=\frac{1}{a^{n}}$. Therefore, $5^{-1}+6^{-1}=\frac{1}{5}+\frac{1}{6}=\frac{1\times6}{5\times6}+\frac{1\times5}{6\times5}=\frac{6+5}{30}=\frac{11}{30}$.
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