Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises: 44

Answer

$\frac{1}{125t^{3}}$

Work Step by Step

According to the negative exponent rule, $a^{-n}=\frac{1}{a^{n}}$. Therefore, $(5t)^{-3}=\frac{1}{(5t)^{3}}=\frac{1}{5^{3}t^{3}}=\frac{1}{125t^{3}}$.
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