Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises - Page 277: 89

Answer

$\frac{s^{12}}{t^{20}}$

Work Step by Step

According to the power rule for exponents, $(a^{m})^{n}=a^{mn}$ (where $m$ and $n$ are integers and $a$ is a real number). Therefore, $(\frac{-s^{3}}{t^{5}})^{4}=(\frac{-1\times s^{3}}{t^{5}})^{4}=\frac{(-1)^{1\times4}s^{3\times4}}{t^{5\times4}}=\frac{(-1)^{4}s^{12}}{t^{20}}=\frac{s^{12}}{t^{20}}$.
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