Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises: 55

Answer

$-\frac{5}{24}$

Work Step by Step

According to the negative exponent rule, $a^{-n}=\frac{1}{a^{n}}$. Therefore, $8^{-1}-3^{-1}=\frac{1}{8}-\frac{1}{3}=\frac{1\times3}{8\times3}-\frac{1\times8}{3\times8}=\frac{3-8}{24}=\frac{-5}{24}=-\frac{5}{24}$.
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