Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises: 46

Answer

$\frac{5}{t^{3}}$

Work Step by Step

According to the negative exponent rule, $a^{-n}=\frac{1}{a^{n}}$. Therefore, $5t^{-3}=\frac{5}{t^{3}}$. Since there are no parentheses around $5t$, the base of the exponent is $t$ (and not $5t$).
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