## Intermediate Algebra (12th Edition)

$\frac{5}{t^{3}}$
According to the negative exponent rule, $a^{-n}=\frac{1}{a^{n}}$. Therefore, $5t^{-3}=\frac{5}{t^{3}}$. Since there are no parentheses around $5t$, the base of the exponent is $t$ (and not $5t$).