Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises: 81

Answer

$\frac{27}{125}$

Work Step by Step

According to the power rule for exponents, $(a^{m})^{n}=a^{mn}$ (where $m$ and $n$ are integers and $a$ is a real number). Therefore, $(\frac{3}{5})^{3}=(\frac{3^{1}}{5^{1}})^{3}=\frac{3^{1\times3}}{5^{1\times3}}=\frac{3^{3}}{5^{3}}=\frac{27}{125}$.
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