Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises: 56

Answer

$-\frac{1}{12}$

Work Step by Step

According to the negative exponent rule, $a^{-n}=\frac{1}{a^{n}}$. Therefore, $6^{-1}-4^{-1}=\frac{1}{6}-\frac{1}{4}=\frac{1\times4}{6\times4}-\frac{1\times6}{4\times6}=\frac{4-6}{24}=\frac{-2}{24}=-\frac{2}{24}=-\frac{1}{12}$.
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