Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises - Page 277: 60

Answer

27

Work Step by Step

According to the negative exponent rule, $a^{-n}=\frac{1}{a^{n}}$. Therefore, $\frac{1}{3^{-3}}=\frac{1}{\frac{1}{3^{3}}}=1\div\frac{1}{3^{3}}=1\times3^{3}=1\times27=27$.
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