Answer
a. B. 3
b. D. -3
c. D. -3
d. B. 3
Work Step by Step
According to the definition of negative exponents $a^{-n}=\frac{1}{a^{n}}$ (where $a\ne0$).
Therefore,
a. $(\frac{1}{3})^{-1}=\frac{1}{(\frac{1}{3})}=3$
b. $(-\frac{1}{3})^{-1}=\frac{1}{(-\frac{1}{3})}=-3$
c. $-(\frac{1}{3})^{-1}=-\frac{1}{(\frac{1}{3})}=-3$
d. $-(-\frac{1}{3})^{-1}=-(\frac{1}{-\frac{1}{3}})=-(-3)=3$