Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.1 - Integer Exponents and Scientific Notation - 4.1 Exercises: 82

Answer

$\frac{16}{9}$

Work Step by Step

According to the power rule for exponents, $(a^{m})^{n}=a^{mn}$ (where $m$ and $n$ are integers and $a$ is a real number). Therefore, $(\frac{4}{3})^{2}=(\frac{4^{1}}{3^{1}})^{2}=\frac{4^{1\times2}}{3^{1\times2}}=\frac{4^{2}}{3^{2}}=\frac{16}{9}$.
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