College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4 - Page 490: 85

Answer

Since $x \ne - 28$, $x = 28$

Work Step by Step

$2 \log x - \log 7 = \log 112$ $\log x^{2} - \log 7= \log 112$ $\log \frac{x^{2}}{7} = \log 112$ $\frac{x^{2}}{7} = 112$ $x^{2} = 784$ $x = ±\sqrt {784}$ $x = ±28$ Since $x \ne - 28$, $x = 28$
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