College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4: 47

Answer

$x=0$

Work Step by Step

Begin by factoring the terms using trial and error. Then set the terms in each set of parentheses equal to $0$ and solve for $x$ by using the natural log on both sides of each equation. $3^{2x}+3{x}-2=0$ $(3^x-1)(3^x+2)=0$ $3^x=1, 3^x=-2$ $x=0$, not possible
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