College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4 - Page 490: 104

Answer

a) The population of Texas in 2010 was $25.1$ million. b) The population of Texas will reach $28$ million in $6$ years in the year $2016$.

Work Step by Step

a) $A = 25.1e^{0.0187t}$ $A = 25.1e^{0.0187(0)}$ $A = 25.1e^{0}$ $A = 25.1(1)$ $A = 25.1$ million The population of Texas in 2010 was $25.1$ million. b) $28 = 25.1e^{0.0187t}$ $\frac{28}{25.1} = e^{0.0187t}$ $\ln \frac{28}{25.1} = 0.0187t$ $t = \frac{\ln \frac{28}{25.1}}{0.0187}$ by GDC / calculator $t = 5.8468...$ years $t \approx 6$ years The population of Texas will reach $28$ million in $6$ years in the year $2016$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.