College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4: 31

Answer

$x=1.30$

Work Step by Step

Divide both sides by $3$. Then make each side a natural log, and pull down the exponent on the left side. Then divide to solve for $x$. $3e^{5x}=1977$ $e^{5x}=659$ $5x\ln(e)=\ln(659)$ $x=\frac{\ln(659)}{5\ln(e)}$ $x=1.30$
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