Answer
$x = -7$
Since $x \ne -7$, there is no answer $=$ no solution.
Work Step by Step
$\log(3x-3) = \log (x+1) + \log 4$
$\log(3x-3) = \log [4(x+1)]$
$\log(3x-3) = \log (4x + 4)$
$\log (3x-3) - \log(4x+4) = 0$
$\log \frac{3x-3}{4x+4} = 0$
$1 = \frac{3x-3}{4x+4} $
$\frac{3x-3}{4x+4} = 1$
$3x - 3 = 1(4x+4)$
$3x - 3 = 4x + 4$
$3x - 4x - 3 - 4 = 0$
$-x - 7 = 0$
$-x = 7$
$x = -7$
Since $x \ne -7$, there is no answer $=$ no solution.
