College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4: 79

Answer

$x = -7$ Since $x \ne -7$, there is no answer $=$ no solution.

Work Step by Step

$\log(3x-3) = \log (x+1) + \log 4$ $\log(3x-3) = \log [4(x+1)]$ $\log(3x-3) = \log (4x + 4)$ $\log (3x-3) - \log(4x+4) = 0$ $\log \frac{3x-3}{4x+4} = 0$ $1 = \frac{3x-3}{4x+4} $ $\frac{3x-3}{4x+4} = 1$ $3x - 3 = 1(4x+4)$ $3x - 3 = 4x + 4$ $3x - 4x - 3 - 4 = 0$ $-x - 7 = 0$ $-x = 7$ $x = -7$ Since $x \ne -7$, there is no answer $=$ no solution.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.