College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4 - Page 490: 35

Answer

$x\approx2.45$

Work Step by Step

Find the natural log of both sides and then pull out the exponent to the left side ($\ln$ and $e$ cancel each other out). Then solve for $x$. $e^{5x-3}-2=10476$ $e^{5x-3}=10478$ $5x-3=\ln(10478)$ $5x=\ln(10478)+3$ $x=\frac{\ln(10478)+3}{5}$ $x\approx2.45$
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