Answer
$x\approx1.58$
Work Step by Step
Begin by factoring the terms using trial and error. Then set the terms in each set of parentheses equal to $0$ and solve for $x$ by using the natural log on both sides of each equation.
$2^{2x}+2^{x}-12=0$
$(2^{x}+4)(2^{x}-3)=0$
$2^{x}=-4, 2^{x}=3$
not possible, $x=\frac{\ln(3)}{\ln(2)}$
$x\approx1.58$
