College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4 - Page 490: 32

Answer

$x=1.32$

Work Step by Step

Divide both sides by $4$. Then make each side a natural log, and pull down the exponent on the left side. Then divide to solve for $x$. $4e^{7x}=10,273$ $e^{7x}=\frac{10,273}{4}$ $7x\ln(e)=\ln(\frac{10,273}{4})$ $x=\frac{\ln(\frac{10,273}{4})}{7\ln(e)}$ $x=1.32$
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