College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4 - Page 490: 84

Answer

$x = 0.20$

Work Step by Step

$\log (x+7) - \log 3 = \log (7x+1)$ $\log \frac{x+7}{3} = \log (7x+1)$ $\log \frac{x+7}{3} - \log (7x+1) = 0$ $\log \frac{x+7}{3(7x+1)} = 0$ $\log \frac{x+7}{21x+3} = 0$ $1 = \frac{x+7}{21x+3}$ $\frac{x+7}{21x+3} = 1$ $x+7 = 1(21x + 3)$ $x+ 7 = 21x + 3$ $x - 21x = - 7 + 3$ $-20x = -4$ $x = \frac{4}{20}$ $x = \frac{1}{5}$ by GDC / calculator $x = 0.20$
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