College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4 - Page 490: 38

Answer

$x\approx6.06$

Work Step by Step

Find the natural log of both sides and then pull out the exponent to the left side. Then solve for $x$. $5^{x-3}=137$ $\ln(5^{x-3})=\ln(137)$ $(x-3)\ln(5)=\ln(137)$ $(x-3)=\frac{\ln(137)}{\ln(5)}$ $x=3+\frac{\ln(137)}{\ln(5)}$ $x\approx6.06$
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