College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4: 30

Answer

$x=2.48$

Work Step by Step

Divide both sides by $9$. Then make each side a natural log, and pull down the exponent on the left side. Then divide to solve for $x$. $9e^x=107$ $e^x=\frac{107}{9}$ $x\ln(e)=\ln(\frac{107}{9})$ $x=\frac{\ln(\frac{107}{9})}{\ln(e)}$ $x=2.48$
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