College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Exponential and Logarithmic Functions - Exercise Set 4.4 - Page 490: 62

Answer

$x\approx74.21$

Work Step by Step

Use the definition of the natural log function to solve for $x$. Rewrite the problem so that the base has the exponent of the opposite side and is equal to the log's number and/or variable. $6\ln2x=30$ $\ln2x=5$ $e^5=2x$ $x=\frac{e^5}{2}$ $x\approx74.21$
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