Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 8 - Potential Energy and Conservation of Energy - Problems: 9b

Answer

$v_f=26.5m/s$

Work Step by Step

Using the conservation of energy formula; $$K_i+U_i=K_f+U_f$$ $$\frac{1}{2}m{v_i}^2+mgh_i=\frac{1}{2}m{v_f}^2+mgh_f$$ $$\frac{1}{2}{v_i}^2+gh_i=\frac{1}{2}{v_f}^2+gh_f$$ $$\frac{1}{2}{(17 m/s)}^2+(9.81 m/s^2)(42.0m)=\frac{1}{2}{v_f}^2+(9.80m/s^2)(21.0 m)$$ $$v_f=26.5m/s$$
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