## Fundamentals of Physics Extended (10th Edition)

In Problem 19d, we found that $\Delta U_{g}$ = 62.7 J. We also know that $\Delta U_{g} = mg\Delta h$. The maximum height above the release point will be equal to the change in height $\Delta h$ from the release point to the maximum height. Solving for $\Delta h$ and plugging in known values we get: $\Delta U_{g} = mg\Delta h$. $\Delta h = \frac{\Delta U_{g}}{mg}$ $\Delta h = \frac{62.7 J}{(8.00 kg)(9.8 m/s²)}$ = 0.800 m = 80.0 cm