## Fundamentals of Physics Extended (10th Edition)

$-183.75J$
The initial potential energy of the ball relative to the ground will be:$Ep_{0}=mgh\left.......( 1\right)$. On the ground: $Ep_{1}=0\left......( 2\right)$ because there is no height difference relative to the ground. So the energy change of snowball during flight will be: $\Delta E_{p}=Ep_{1}-Ep_{0}=-mgh(3)\approx -183.75J$. Lets assume the potential energy at the top is zero ($E_{p0}=0$). Using (3), we get $\Delta E_{p}=Ep_{1}-Ep_{0}=-mgh\Rightarrow -mgh=Ep_{1}-0\Rightarrow Ep_{1}=-mgh\approx -183.75J$