Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 8 - Potential Energy and Conservation of Energy - Problems - Page 203: 8c


$ -183.75J$

Work Step by Step

The initial potential energy of the ball relative to the ground will be:$Ep_{0}=mgh\left.......( 1\right) $. On the ground: $Ep_{1}=0\left......( 2\right) $ because there is no height difference relative to the ground. So the energy change of snowball during flight will be: $\Delta E_{p}=Ep_{1}-Ep_{0}=-mgh(3)\approx -183.75J$. Lets assume the potential energy at the top is zero ($E_{p0}=0$). Using (3), we get $\Delta E_{p}=Ep_{1}-Ep_{0}=-mgh\Rightarrow -mgh=Ep_{1}-0\Rightarrow Ep_{1}=-mgh\approx -183.75J$
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