Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 8 - Potential Energy and Conservation of Energy - Problems: 12a

Answer

$v_{B}=\sqrt {v^{2}_{0}+2gh}\left( 3\right) \approx 21\dfrac {m}{s}$

Work Step by Step

The total energy of snowball respect to the ground initially will be: $E_{tot}=E_{k0}+E_{p0}=\dfrac {mv^{2}_{0}}{2}+mgh(1)$ Total energy of snowball is conserved so when it hits the ground lets write total energy of snowball respect to ground again : $ E_{tot}=E_{kB}+E_{pB}=\dfrac {mv^{2}_{B}}{2}+0\left( 2\right) $ so from (1) and (2) we get: $v_{B}=\sqrt {v^{2}_{0}+2gh}\left( 3\right) \approx 21\dfrac {m}{s}$
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