Answer
$1250J$
Work Step by Step
As we know that
$W=\frac{1}{2}Kx^{2}$
Putting the values in:
$W$=$\frac{1}{2}\times100(5)^2$
$W$=$50\times25$
$W$=$1250J$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 7 - Kinetic Energy and Work - Problems - Page 172: 28
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