## Fundamentals of Physics Extended (10th Edition)

Published by Wiley

# Chapter 7 - Kinetic Energy and Work - Problems: 22b

#### Answer

Please see the work below.

#### Work Step by Step

We know that $W_2-mgd=\Delta K_2=0$ This can be rearranged as: $W_2=mgd$ We plug in the known values to obtain: $W_2=(80.0)(9.80)(10.0)=7.84\times 10^3J$

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