Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 7 - Kinetic Energy and Work - Problems: 21c

Answer

Kinetic energy of the block $= \frac{Mgd}{4}$

Work Step by Step

Kinetic energy $= \frac{1}{2}Mv^{2}$ To find the expression for $v^{2}$, we use: $v^{2}=u^{2}+2ad $ $v^{2}=2\times \frac{g}{4} \times d=\frac{gd}{2}$ Plugging in respective values, we get: Kinetic energy $=\frac{1}{2}M\times \frac{gd}{2} = \frac{Mgd}{4}$
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