Answer
Kinetic energy of the block $= \frac{1}{4}mgd$
Work Step by Step
We know that $\Delta K=W_{g}+W_{T}$, where $W_{g}=mgd$ and $W_{T}=-\frac{3}{4}mgd$
Now, we get
$$\Delta K=W_{g}+W_{T}=mgd-\frac{3}{4}mgd=\frac{1}{4}mgd$$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 7 - Kinetic Energy and Work - Problems - Page 172: 21c
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
