Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 7 - Kinetic Energy and Work - Problems - Page 172: 23

Answer

Please see the work below.

Work Step by Step

We know that in the given scenario, the work done due to applied force that is $W_a$ is equal to work done due to gravity that is $W_g$; $W_a=W_g$ $W_a=mgh$ We plug in the known values to obtain: $W_a=(3.00)(9.8)(0.150)$ $W_a=4.41J$
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