Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 7 - Kinetic Energy and Work - Problems: 23

Answer

Please see the work below.

Work Step by Step

We know that in the given scenario, the work done due to applied force that is $W_a$ is equal to work done due to gravity that is $W_g$; $W_a=W_g$ $W_a=mgh$ We plug in the known values to obtain: $W_a=(3.00)(9.8)(0.150)$ $W_a=4.41J$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.