Answer
Please see the work below.
Work Step by Step
We know that:
$W_3=mgd-\frac{1}{2}mv_1^2$
We plug in the known values to obtain:
$W_3=(80.0)(9.80)(10.0)-\frac{1}{2}(80.0)(5.00)=6.84\times 10^3J$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 7 - Kinetic Energy and Work - Problems - Page 172: 22c
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