Answer
Please see the work below.
Work Step by Step
We know that:
$W_1-mgd=\Delta K_1=\frac{1}{2}mv_1^2$
This can be rearranged as:
$W_1=mgd+\frac{1}{2}mv_1^2$
We plug in the known values to obtain:
$W_1=80.0(9.8)(10.0)+\frac{1}{2}(80.0)(5.00)=8.84\times 10^3J$
