Answer
$Z = 206~\Omega$
Work Step by Step
We can find $Z$:
$Z = \sqrt{R^2+(X_L-X_C)^2}$
$Z = \sqrt{R^2+(\omega_d~L-\frac{1}{\omega_d~C})^2}$
$Z = \sqrt{R^2+(2\pi~f_d~L-\frac{1}{2\pi~f_d~C})^2}$
$Z = \sqrt{(200~\Omega)^2+[(2\pi)(60.0~Hz)(0.230~H)-\frac{1}{(2\pi)~(60.0~Hz)~(70.0\times 10^{-6}~F)}]^2}$
$Z = 206~\Omega$
