Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 31 - Electromagnetic Oscillations and Alternating Current - Problems - Page 937: 31b

Answer

The reactance is $~~24.5~\Omega$

Work Step by Step

In part (a), we found that $~~\omega_d = 4082.5~rad/s$ We can find the reactance: $X_L = \omega_d~L$ $X_L = (4082.5~rad/s)(6.0\times 10^{-3}~H)$ $X_L = 24.5~\Omega$ The reactance is $~~24.5~\Omega$
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