Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 31 - Electromagnetic Oscillations and Alternating Current - Problems - Page 937: 32a

Answer

The maximum value of the current is $~~5.22~mA$

Work Step by Step

We can find the maximum value of the current: $I_L = \frac{V_L}{X_L}$ $I_L = \frac{V_L}{\omega_d~L}$ $I_L = \frac{25.0~V}{(377~rad/s)(12.7~H)}$ $I_L = 5.22~mA$ The maximum value of the current is $~~5.22~mA$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.

GradeSaver will pay $15 for your literature essays
GradeSaver will pay $25 for your college application essays
GradeSaver will pay $50 for your graduate school essays – Law, Business, or Medical
GradeSaver will pay $10 for your Community Note contributions