Answer
$Z = 267~\Omega$
Work Step by Step
We can find $Z$:
$Z = \sqrt{R^2+X_C^2}$
$Z = \sqrt{R^2+(\frac{1}{\omega_d~C})^2}$
$Z = \sqrt{R^2+(\frac{1}{2\pi~f_d~C})^2}$
$Z = \sqrt{(200~\Omega)^2+[\frac{1}{(2\pi)~(60.0~Hz)~(15.0\times 10^{-6}~F)}]^2}$
$Z = 267~\Omega$
