Answer
The maximum value of the current is $~~39.1~mA$
Work Step by Step
We can find the maximum value of the current:
$I_C~X_C = V_C$
$\frac{I_C}{\omega_d~C} = V_C$
$I_C = V_C~\omega_d~C$
$I_C = (25.0~V)(377~rad/s)(4.15\times 10^{-6}~F)$
$I_C = 39.1~mA$
The maximum value of the current is $~~39.1~mA$
